(y-15)/(y^2-4y-32)

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Solution for (y-15)/(y^2-4y-32) equation: 


D( y )

y^2-(4*y)-32 = 0

y^2-(4*y)-32 = 0

y^2-(4*y)-32 = 0

y^2-4*y-32 = 0

y^2-4*y-32 = 0

DELTA = (-4)^2-(-32*1*4)

DELTA = 144

DELTA > 0

y = (144^(1/2)+4)/(1*2) or y = (4-144^(1/2))/(1*2)

y = 8 or y = -4

y in (-oo:-4) U (-4:8) U (8:+oo)

(y-15)/(y^2-(4*y)-32) = 0

(y-15)/(y^2-4*y-32) = 0

y^2-4*y-32 = 0

y^2-4*y-32 = 0

DELTA = (-4)^2-(-32*1*4)

DELTA = 144

DELTA > 0

y = (144^(1/2)+4)/(1*2) or y = (4-144^(1/2))/(1*2)

y = 8 or y = -4

(y+4)*(y-8) = 0

(y-15)/((y+4)*(y-8)) = 0

y-15 = 0 // + 15

y = 15

y = 15

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